C#文件传输 – CodeClip

今天终于把文件传输问题给研究明白了，特发此代码用来帮助正在学习的人们。

发送代码：

string path = “E:\\c#\\convey_file\\convey_file\\Form1.cs”; //要传输的文件

TcpClient client = new TcpClient();

client.Connect(IPAddress.Parse(“192.168.0.52”),9999);

FileStream file = new FileStream(path,FileMode.Open,FileAccess.Read); //注意与receive的filestream的区别

BinaryReader binaryreader = new BinaryReader(file);

byte[] b = new byte[4098];

int data;

Console.WriteLine(“正在发送文件”);

while ((data = binaryreader.Read(b, 0, 4098)) != 0) //这个注意是将文件写成流的形式

{

client.Client.Send(b,data,SocketFlags.None); //发送文件流到目标机器

}

client.Client.Shutdown(SocketShutdown.Both);

binaryreader.Close();

file.Close();

接收代码：

private Socket s;

TcpListener tl;

public void lis()

{

string path = “d:\\1.cs”; //要传入文件的路径

tl = new TcpListener(9999);

tl.Start();

Console.WriteLine(“等待接受”);

s = tl.AcceptSocket();

FileStream fs = new FileStream(path, FileMode.OpenOrCreate, FileAccess.Write); //注意这个的属性和send端有所不同

BinaryWriter binarywrite = new BinaryWriter(fs);

int count;

byte[] b = new byte[4098];

while ((count = s.Receive(b, 4098, SocketFlags.None)) != 0) //这个是接受文件流

{

binarywrite.Write(b,0,count); //将接收的流用写成文件

}

binarywrite.Close();

fs.Close();

s.Close();

tl.Stop();

Console.WriteLine(“文件传输完毕”);

}